What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?

Answer:(x + 3)^2 + (y + 1)^2 = 25Step-by-step explanation:Equation of a circle with center (h, k) and radius, r.(x - h)^2 + (y - k)^2 = r^2The center is (-3, -1), so h = 1, and k = 2.(x - (-3))^2 + (y - (-1))^2 = r^2(x + 3)^2 + (y + 1)^2 = r^2Now we substitute x and y with the values of x and y from the given point, and we solve for r^2.(1 + 3)^2 + (2 + 1)^2 = r^24^2 + 3^2 = r^216 + 9 = r^2r^2 = 25Now that we know r^2, we substitute it into the equation above.(x + 3)^2 + (y + 1)^2 = 25