MATH SOLVE

3 months ago

Q:
# The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend)?A. 3a=48B. a(a+1)(a+2)=48C. a+(a-1)+(a-2)=48D. a+(a+1)+(a+2)=48

Accepted Solution

A:

three consecutive numbers....a, a + 1, a + 2

together their ages total 48 years

a + (a + 1) + (a + 2) = 48 <== ur equation

3a + 3 = 48

3a = 48 - 3

3a = 45

a = 45/3

a = 15

a + 1 = 15 + 1 = 16

a + 2 = 15 + 2 = 17

so their ages are : 15,16,17

together their ages total 48 years

a + (a + 1) + (a + 2) = 48 <== ur equation

3a + 3 = 48

3a = 48 - 3

3a = 45

a = 45/3

a = 15

a + 1 = 15 + 1 = 16

a + 2 = 15 + 2 = 17

so their ages are : 15,16,17