The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend)?A. 3a=48B. a(a+1)(a+2)=48C. a+(a-1)+(a-2)=48D. a+(a+1)+(a+2)=48
Accepted Solution
A:
three consecutive numbers....a, a + 1, a + 2 together their ages total 48 years
a + (a + 1) + (a + 2) = 48 <== ur equation 3a + 3 = 48 3a = 48 - 3 3a = 45 a = 45/3 a = 15