MATH SOLVE

2 months ago

Q:
# what’s the solution to x-4y=-8 and 2x-3y=-16

Accepted Solution

A:

Answer: [tex]x=-8\\y=0[/tex]Step-by-step explanation: You can apply the elimination method: - Multiply the first equation by -2. - Add both equations to cancel out the variable x. - Solve for y: [tex]\left \{ {{(-2)(x-4y)=-8(-2)} \atop {2x-3y=-16}} \right.\\\\\\\left \{ {{-2x+8y=16} \atop {2x-3y=-16}} \right.\\ ------\\5y=0\\y=0[/tex] - Substitute y=0 into any of the original equations ans solve for x. Then: [tex]x-4(0)=-8\\x=-8[/tex]