y = βˆ’(x + 4)2 βˆ’ 7 vertex

Accepted Solution

Answer:The vertex (h,k) is (-4,-7).Step-by-step explanation:I assume you are looking for the vertex [tex]y=-4(x+4)^2-7[/tex].The vertex form of a quadratic is [tex]y=a(x-h)^2+k[/tex] where the vertex is (h,k) and a tells us if the parabola is open down (if a<0) or up (if a>0). a also tells us if it is stretched or compressed.Anyways if you compare [tex]y=-4(x+4)^2-7[/tex] to [tex]y=a(x-h)^2+k[/tex] , you should see that [tex]a=-4,h=-4,k=-7[/tex].So the vertex (h,k) is (-4,-7).